What is the mole ratio of alcl3?
Mole ratio in balanced equation is 2 : 3 for Al : Cl2, so you need 1.5 times as much Cl2 as you have Al.
How many moles are in 32.5 g of aluminum chloride alcl3 )?
The number of moles of aluminum chloride for the given amount is 0.244 moles.
How many grams of AlCl3 are formed?
In order to find the amount of any product formed, you start with the amount of the limiting reactant formed, in this case 7.80 g HCl. The calculation should be as follows: (7.80 g HCl)*(1 mol HCl/36.45 g HCl)*(2 mol AlCl3/6 mol HCl)*(133.33 g AlCl3/1 mol AlCl3)= 9.51 g AlCl3.
What is the N factor of AlCl3?
Aluminium chloride doesn’t have valency. It is a compound and the valencies of constituent atoms are satisfied. Aluminium had a valency of + 3 and each chlorine atom had a valencyof -1. … Anyways, the valency of Aluminum in Aluminum Chloride is +3.
How many grams of aluminum chloride will be produced if 2.50 moles of aluminum react?
Answer to Question #162269 in General Chemistry for ian. How many grams of AlCl3 will be produced if 2.50 moles of Al react? The coefficients before Al and AlCl3 are equal, so from 2.50 moles of Al 2.50 moles of AlCl3 are obtained. m(AlCl3)=2.50*133.5=333.75(g).
How many grams are in 88.1 moles?
How many grams are in 88.1 moles of magnesium? 88.1 molx 24.3059 = 21409.