# How many moles of oxygen are produced by the decomposition of 6 0 moles of potassium chlorate?

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## How many moles of oxygen can be obtained by the decomposition?

The correct answer of this question is 5 moles of oxygen gas can be produced during the electrolytic decomposition of 180 g of water.

## How many moles of oxygen gas are produced by the decomposition of 245 g of potassium chlorate?

The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose.

## How many moles of KClO3 are required for producing 2.4 moles of oxygen?

Answer: The amount of KClO3 required 196 g. Given: 196 g of is requires to produce 2.4 moles of oxygen.

## How many moles of oxygen are in 2KClO3?

2KClO3 –> 2KCl + 3O2

(3/2)*(3.0) moles O2, or 4.5 moles of O2.

## How much oxygen will be obtained by the complete electrolysis of 90 kg of water 2h2o → 2h2 O2?

H2O → H2 + O2

In water, the ratio of the mass of hydrogen to that of oxygen is 1:8. So, when water decomposes, it produces hydrogen and oxygen in the ratio of 1:8. So, when 90 kg of water decomposes, 10 kg of hydrogen and 80kg of oxygen is produced.

## How many moles of oxygen are evolved?

How many moles of oxygen are evolved? 1 Expert Answer Assuming that only oxygen evaporated, you can figure out the moles by dividing the difference in weight of the mixture by the molecular weight of the oxygen. So the answer would be (23.584-22.347)grams divided by 16.000 g/mol, or 7.7313×10^-2 moles O2.

## How many moles of oxygen atoms are in 90 grams of water?

A mole of a compound is a number of grams equal to the atomic weight of a molecule of the compound, so for water we have 2 hydrogen atoms and one oxygen, so the atomic weight of water is 1+1+16=18, so a mole of water is 18 grams. We have 90g of water so we have 90/18 = 5 moles of water.

## How many moles of HGO are needed to produce 125 grams of oxygen?

Since we have the mass of O2 we can calculate the moles as moles = mass/RMM where RMM is the relative molecular mass of O2, which is 32 g/mol. Therefore the number of moles = 125/16 = 3.9 mol.

## How many moles of water are produced from the reaction of oxygen with four moles of propane?

This tells us that 4 moles of water are produced for every 1 mole of propane. This is a conversion factor for this reaction: (4 moles H2O/1 mole C3H6). Since we consume all 2.08 moles of propane, we’ll produce: (2.08 moles C3H8)*(4 moles H2O/1 mole C3H6) = 8.32 moles H2O.

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## How many grams of oxygen can be produced from the decomposition of KClO3?

1 g of KClO3 would yield 0.783353733 g of O2.

## How many moles of potassium nitrate are produced when?

So clearly 1 mole of each reactant combines to form 3 moles potassium nitrate and 1 mole aluminium phosphate. Hence, by ratio and proportion, 2 moles of each reactant will produce 6 moles potassium nitrate and 2 moles aluminium phosphate.