# Your question: What is the volume occupied by 1 mole of nitrogen at STP?

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## How do you find the volume of a nitrogen gas at STP?

Multiply the coefficient 0.022414 by the number of moles to calculate the gas volume (in cubic meters) at the standard temperature and pressure. In our example, the volume of the nitrogen gas is 0.022414 x 2 = 0.044828 cubic meters or 44.828 liters.

## What is the volume of 7g nitrogen at STP?

= 5.6 litres of volume.

## What is the volume of 2 moles of nitrogen gas?

What is the volume of two moles of diatomic nitrogen gas at STP? Explanation: One mole of gas has a volume of 22.4L at STP. Since there are two moles of gas present, the volume is doubled.

## What is the ratio of volume of 1 mole of nitrogen gas?

Option 1, 1 : 0.5

So, Volume of one mole of N2 occupies 22.4 litres.

## What is the volume of 1.0 mole of gas at STP conditions?

At Standard Temperature and Pressure (STP), 1 mole of any gas will occupy a volume of 22.4 L.

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## What is STP formula?

VSTP = V * (273.15/T) * (P/760) This STP formula uses Kelvins, Torrs and Liters.

## What is the volume formula?

Whereas the basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.

## What is the volume occupied by 28 U nitrogen gas?

so, 22.4L/6.022*10^23=3.72*10^23.

## What is the volume of 14 gram of nitrogen gas at STP?

So 14g N2 will occupy 22.4/2=11.2L at STP.

## What is the volume at STP of 2.8 g of nitrogen gas?

So N2 = 2*14 = 28 g/mol. (2.8 / 28 )moles = 0.1 mole. So the gas will occupy a volume of 0.1 * 22.4 = 2.24 L of volume.